[Asterisk-Users] Queue.conf, maxlen = 5 , but what happens with the 6. caller ?

[Stig Thune]

In my queue.conf I have:

; Maximum number of people waiting in the queue (0 for unlimited)
;
maxlen = 5

---------

Log: 

-- Executing Goto("SIP/242.112.162.21-081a8b90", "veksel|s|1") in new stack

    -- Goto (veksel,s,1)

    -- Executing Answer("SIP/242.112.162.21-081a8b90", "") in new stack

    -- Executing SetMusicOnHold("SIP/242.112.162.21-081a8b90", "default") in new stack

    -- Executing BackGround("SIP/242.112.162.21-081a8b90", "/usr/src/asterisk/sounds/ownits/veksel") in new stack

    -- Playing '/usr/src/asterisk/sounds/ownits/veksel' (language 'en')

    -- Executing Wait("SIP/242.112.162.21-081a8b90", "1") in new stack

    -- Stopped music on hold on SIP/myserver.se-08157eb0

    -- Playing 'queue-thereare' (language 'en')

    -- Executing Queue("SIP/242.112.162.21-081a8b90", "help-privatanslutningar-queue|t") in new stack

Oct 29 15:15:15 WARNING[1572884]: app_queue.c:1700 queue_exec: Unable to join queue 'help-tech-queue'

------

Solution - but how ?

Because of bandwidth limitations, I have to reduce the incomming calls to 5.
So when people call, and are placed in queue.. and the 6. caller comes in, he/she
gets a welcome message, and then is left with a "empty sound".

How can I change, so that the 6. caller gets a message like:

"there are to many callers, please try again later".
..and the the call is hung up.

/ Stig Henning


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