[Asterisk-Users] Re: Asterisk-Users digest, Vol 1 #3276 - 7 msgs

[Darnell Gadberry]

Sam,

I too am experiencing a similar problem with the VoicePulse LA 
exchange. I have
two VoicePulse DID numbers 212 XXX and 213 XXX. Both numbers terminate 
in the same
Asterisk context on my server. DTMF is being passed-through properly on 
the 212 number but
not the 213.

I have sent VoicePulse tech support several emails regarding the 
problem. They confirmed
the existence of the problem and promised a fix and associated server 
restart last Friday.
Unfortunately, it appears that they either FORGOT to fix the problem or 
simply did not
have the promised fix.

I am seriously considering purchasing a PRI, a block of 213 XXX DID 
numbers and terminating
the circuit on a Cisco AS5300 to provide inbound calling for my friends 
and customers
using Asterisk on a cost-plus basis. Please contact me off-list if you 
are interested.

- darnell gadberry

------------------------------------------
Darnell Gadberry
President
binaryMedia
darnell AT binmedia DOT com

On Mar 31, 2004, at 4:02 AM, asterisk-users-request at lists.digium.com 
wrote:

> Message: 4
> Date: Wed, 31 Mar 2004 02:30:55 -0800
> From: "Sam Bacsa" <sbacsa at infiniteray.com>
> To: <asterisk-users at lists.digium.com>
> Subject: [Asterisk-Users] VoicePulse Connect & DTMF Tones
> Reply-To: asterisk-users at lists.digium.com
>
> I am using VoicePulse Connect! to connect to my Asterisk server through
> IAX2.
>
> It appears that when anyone dials my DID and proceeds to dial an
> extension when prompted, the DTMF tones are not received by the server
> (as in, the server continues to play the incoming message in a loop, 
> not
> realizing an extension has been entered).  I have even tried
> automatically transferring to a VM box and seeing if I can log in -- I
> cannot.
>
> Is there any way to fix this?  What are the configuration parameters to
> get DTMF to work on incoming calls?
>
> I am 100% sure that my extensions.conf configuration is in order, so it
> is not an Asterisk problem.
>
> Please Help!
>
>
> Thanks,
> Sam Bacsa