<br><br><div class="gmail_quote">2011/1/11 Kevin P. Fleming <span dir="ltr"><<a href="mailto:kpfleming@digium.com">kpfleming@digium.com</a>></span><br><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
On 01/11/2011 11:50 AM, Olivier wrote:<br>
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2011/1/11 Lenz Emilitri <<a href="mailto:lenz.loway@gmail.com" target="_blank">lenz.loway@gmail.com</a> <mailto:<a href="mailto:lenz.loway@gmail.com" target="_blank">lenz.loway@gmail.com</a>>><div class="im">
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Why not an unattended transfer to the queue itself, or a different<br>
queue?<br>
l.<br>
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I was afraid that the incoming call could be presented to the same agent<br>
again.<br>
Thinking back about it, it seems to fit what I'm after.<br>
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If there is a call leg out to the agent that is in 'ringing' state, then issuing a Hangup on that call leg is not going to affect the call sitting in the queue waiting for an agent to answer... they are not connected to each other until the agent answers and the queue application connects them together. Issuing an AMI Hangup on the call leg that is ringing the agent's phone is exactly what you want to do.<br>
</blockquote><div><br>Thanks for clarifying this !<br>Cheers <br></div><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;"><font color="#888888">
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Kevin P. Fleming<br>
Digium, Inc. | Director of Software Technologies<br>
445 Jan Davis Drive NW - Huntsville, AL 35806 - USA<br>
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