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</o:shapelayout></xml><![endif]--></head><body lang=EN-GB link=blue vlink=purple><div class=WordSection1><p class=MsoNormal>Hi,<o:p></o:p></p><p class=MsoNormal><o:p> </o:p></p><p class=MsoNormal>I’m trying to create a link between two PBXs. One is Asterisk 1.4.15, the other is an unknown 3<sup>rd</sup> party PBX.<o:p></o:p></p><p class=MsoNormal><o:p> </o:p></p><p class=MsoNormal>In my internal testing, beween two A*k servers, I found that if I created two sip accounts from the same IP, one as peer and one as user (intending to give an –IN and –OUT setup), then inbound calls always seemed to route via the –OUT account and failed. My fix was to use type=friend, which seemed to make sense and be ok.<o:p></o:p></p><p class=MsoNormal><o:p> </o:p></p><p class=MsoNormal>Now with the 3<sup>rd</sup> party PBX, if I set type=friend, then we get an error of “Peer is not supposed to register”. If I then set type=peer, it registers ok… But I thought that friend=peer+user ??<o:p></o:p></p><p class=MsoNormal><o:p> </o:p></p><p class=MsoNormal><span lang=EN-US>Thanks,<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-US>Adrian<o:p></o:p></span></p><p class=MsoNormal><o:p> </o:p></p></div></body></html>