[asterisk-users] Problem with REMAINDER? 957%60 be 15 remainder 57 not 15 remainder -3 ?
James Cloos
cloos at jhcloos.com
Fri Oct 21 16:44:06 CDT 2016
I saw this on the bug list first and sent a reply, but for the archives
I'll copy it here, too.
REMAINDER() calls libm's remainder(3) or remainderl(3), infix % calls
fmod(3) or fmodl(3).
remainder(3) is defined to round the quotient to the nearest int (always
using round-to-even, notsithstanding the rounding mode), fmod(3) is
defined to trunc(3)ate the quotient.
So the result of x%y will always be in the range [0,x] and the results
of remainder(x,y) will be in the range (-y/2,y/2].
-JimC
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James Cloos <cloos at jhcloos.com> OpenPGP: 0x997A9F17ED7DAEA6
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