[asterisk-users] RES: How to dial extensions asynchronous-sequentially ?

[SamyGo]

All I can focus now is "the objective is to see if there is an way to
deliver more than one SIP 183 message to the caller"

6001 has a song playing in 183 and 6002 has a "service unavailable"
message, do you intend to deliver both of them simultaneously to the
caller? I've seen multiple 183 Session Progress messages getting delivered
to caller but what is your end game ? Play all sort of messages to the
caller together ?

Whoever told you about Asterisk not letting 183 go to the caller with this
dialstring was right. If you want all 183 msgs coming from all parties to
be heard by the caller then I suggest you create a conference, and call the
6001, and 6002 as its participant. Thats the only place where I believe the
audio from different channel is mixed and streamed to users.

>From SIP protocol perspective even if multiple 183 Session Progress
messages reach to the Caller with each message pointing to different
sources, the caller's UAC should ideally pick only one of them, the latest
one I believe.

BR,
Sammy


On Mon, Jul 13, 2015 at 3:51 PM, Rodrigo Pimenta Carvalho <pimenta at inatel.br
> wrote:

> Hi SamyGo.
>
> Thank you for the replay. So, let me explain it better:
>
> I knew that I could use something like " same =
> n,Dial(PJSIP/6001&PJSIP/6002)  ".
> While every extension (called phones) rings and before anyone answers, SIP
> 183 messages will be sent to Asterisk from callees. If a called phone
> answer, the others will be hanged up. It is ok for me. I want to connect
> the caller just to the first called party that answers.
> Yes, it is some sort of ring group implementation where users are dialled
> and just the first one to answer will get the call.
>
> If I just do " same = n,Dial(PJSIP/6001) ", there will be a SIP 183
> message from 6001 to the caller. The caller will really receive that SIP
> 183 message. In this case, Asterisk seems to work as a proxy.
> However, if I do " same = n,Dial(PJSIP/6001&PJSIP/6002)  ", the caller
> will not receive those SIP 183 messages from 6001 and 6002. In this case
> asterisk seems to work different of a proxy, as someone told me in this
> list.
>
> So, if I dial 6001 and 6002, but in asynchronous and sequentially way, I
> will have a chance to see if the caller will receive the SIP 183 messages
> from 6001 and 6002. That it, the objective is to see if there is an way to
> deliver more than one SIP 183 message to the caller, in a kind of  ring
> group implementation.
>
> Any hint will be very helpful!!
>
> Thanks a lot!
>
>
> RODRIGO PIMENTA CARVALHO
> Inatel Competence Center
> Software
> Ph: +55 35 3471 9200 RAMAL 979
> ________________________________________
> De: asterisk-users-bounces at lists.digium.com [
> asterisk-users-bounces at lists.digium.com] em Nome de SamyGo [
> govoiper at gmail.com]
> Enviado: segunda-feira, 13 de julho de 2015 16:24
> Para: Asterisk Users Mailing List - Non-Commercial Discussion
> Assunto: Re: [asterisk-users] How to dial extensions
> asynchronous-sequentially ?
>
> Hi,
> Even you achieve that, what would be the objective? Do you want to just
> call the user and Hangup ? or Dial two users and connect them together ? Is
> this some sort of ring group implementation where users are dialled and
> first one to answer will get the call ??
>
> Anyway here's one way of how I think you can do.
>
> Have a context created to dial the individual user
>
> [dial_user]
> exten => _600X.,1,Dial(PJSIP/${EXTEN})
> ...
>
> and in your code change it to.
>
> same = n,Dial(local/6001 at dial_user/n&local/6002 at dial_user/n)
> same = n,Hangup()
>
>
>
> On Mon, Jul 13, 2015 at 2:28 PM, Rodrigo Pimenta Carvalho <
> pimenta at inatel.br<mailto:pimenta at inatel.br>> wrote:
>
> Hi.
>
>
> I my dialplan I have :
>
> same = n,Dial(PJSIP/6001,10)
> same = n,Dial(PJSIP/6002,30)
> same = n,Hangup()
>
>
> The extension 6002 will not be invited  until the called party 6001 hangs
> up or until 10 seconds if nobody answers the call in 6001.
>
> How to call 6001 and immediately call 6002, having 2 phones ringing at
> same time, but without doing something like this : same =
> n,Dial(PJSIP/6001&PJSIP/6002) ?
> What I'm asking is if it is possible to call 6001 in an asynchronous way
> and then call 6002 too. Is it possible?
>
> Any hint will be very helpful!
>
>
>
> Best regards.
>
>
>
> RODRIGO PIMENTA CARVALHO
> Inatel Competence Center
> Software
> Ph: +55 35 3471 9200<tel:%2B55%2035%203471%209200> RAMAL 979
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