[asterisk-users] Filtering on from caller id
Peter den Hartog
peterdenhartog at gmail.com
Fri Mar 25 03:14:45 CDT 2011
That sounds good but, i would like it the other way arround. I have over 90
extensions that are NOT allowed to use the trunk, and 2 that are.. So
blacklisting everything will take for ever ;D.
On Thu, Mar 24, 2011 at 10:01 PM, Danny Nicholas <danny at debsinc.com> wrote:
> Just use “Ex-girlfriend” logic on your dial command to zap 103 when he
> tries to use the trunk. For each dial command in your dialplan that
> addresses the trunk (let’s call it DAHDI/1 for brevity), duplicate the line
> like this:
>
> Existing:
>
> Exten => _X.,1,Dial(DAHDI/1,w,5551212)
>
> New:
>
> Exten => _X,1,noop(everybody but 103 dials)
>
> Exten => _X./103,n,hangup
>
> Exten => _X.,n,Dial(DAHDI/1,w,5551212)
>
>
> ------------------------------
>
> *From:* asterisk-users-bounces at lists.digium.com [mailto:
> asterisk-users-bounces at lists.digium.com] *On Behalf Of *Peter den Hartog
> *Sent:* Thursday, March 24, 2011 3:45 PM
>
> *To:* Asterisk Users Mailing List - Non-Commercial Discussion
> *Subject:* Re: [asterisk-users] Filtering on from caller id
>
>
>
> Hmm are those extensions then still able to call each other?
>
>
>
> I'll put it more clear,
>
>
>
> I have:
>
> 100, 101, & 103.
>
> A Trunk.
>
>
>
> 100 & 101 are allowed to call over the trunk. but 103, is only allowed to
> call with 100 & 101, of course 100 & 101 should still be able to call 103.
>
>
>
> On Thu, Mar 24, 2011 at 5:14 PM, A J Stiles <asterisk_list at earthshod.co.uk>
> wrote:
>
> On Thursday 24 Mar 2011, Peter den Hartog wrote:
>
> > I would like to use the from caller id, to allow calls yes or no.
> > 101, and 111 should be allowed to use the Trunk, the rest of the phones
> are
> > not.
> >
> > Is this even possible?
> > So if the from caller id is 101 or 111, then allow the call, otherwise
> > hangup.
>
> Would it not be simpler just to put those extensions into a separate
> context,
> which allows trunk calls?
>
> --
> AJS
>
> Answers come *after* questions.
>
> --
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