[asterisk-users] 1.8 realtime - segfault

Naomi Rosenberg naomi at dmcip.com
Mon Mar 21 12:24:14 CDT 2011


> We'd need to see the backtrace, but possible.

Is this any use?

#0  0x00007f61ae1dfb52 in ?? () from /lib/libc.so.6
#1  0x00000000004f88dd in ast_sockaddr_resolve (addrs=0x7f618ce91770, str=0x0, flags=0, family=2) at netsock2.c:235
#2  0x00007f6197c2be9a in ast_sockaddr_resolve_first_af (addr=0x8543f40, name=0x0, flag=0, family=2) at chan_sip.c:28114
#3  0x00007f6197c2bf84 in ast_sockaddr_resolve_first (addr=0x8543f40, name=0x0, flag=0) at chan_sip.c:28135
#4  0x00007f6197bd9693 in __set_address_from_contact (fullcontact=0x862146 "", addr=0x8543f40, tcp=0) at chan_sip.c:12932
#5  0x00007f6197bd97fd in set_address_from_contact (pvt=0x8543af8) at chan_sip.c:12961
#6  0x00007f6197bfafd1 in handle_response_invite (p=0x8543af8, resp=200, rest=0x8541314 "OK", req=0x7f618ce92300, seqno=102) at chan_sip.c:18994
#7  0x00007f6197bff77e in handle_response (p=0x8543af8, resp=200, rest=0x8541314 "OK", req=0x7f618ce92300, seqno=102) at chan_sip.c:19746
#8  0x00007f6197c10882 in handle_incoming (p=0x8543af8, req=0x7f618ce92300, addr=0x7f618ce92270, recount=0x7f618ce92204, nounlock=0x7f618ce92200)
    at chan_sip.c:23624
#9  0x00007f6197c125d5 in handle_request_do (req=0x7f618ce92300, addr=0x7f618ce92270) at chan_sip.c:24036
#10 0x00007f6197c11e64 in sipsock_read (id=0x8172300, fd=16, events=1, ignore=0x0) at chan_sip.c:23934
#11 0x00000000004d881e in ast_io_wait (ioc=0x8144f90, howlong=995) at io.c:288
#12 0x00007f6197c13c48 in do_monitor (data=0x0) at chan_sip.c:24451
#13 0x000000000055b8b6 in dummy_start (data=0x81700e0) at utils.c:971
#14 0x00007f61ad9fa8ba in start_thread () from /lib/libpthread.so.0
#15 0x00007f61ae23302d in clone () from /lib/libc.so.6
#16 0x0000000000000000 in ?? ()


I did this for 3 different segfault occurrences and the output was basically the same, so I think it is representative.
I also followed some different instructions and got a really long backtrace with 45 threads, let me know if you want that.

Thanks
Naomi



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