[asterisk-users] queue show name - callerID

[Örn Arnarson]

There's not any direct way of which I am aware in a single command, but from
the shell you could do the following (and yes, this is a bit of a hack):

for i in `rasterisk -x "queue show" |grep wait |awk -F" " '{print $2}'`; do
rasterisk -x "core show channel $i" | grep "Caller ID";done

That will return (in order) the calls in your queue, their caller-ids and
caller id names. If the caller-id and caller-id-name are the same, each
entry will just be 2 repeating lines.

To skip the second entry (caller-id name), you can just add a colon to the
last grep command, like so:
for i in `rasterisk -x "queue show" |grep wait |awk -F" " '{print $2}'`; do
rasterisk -x "core show channel $i" | grep "Caller ID:";done

What this does, essentially, is check the callers' channels in the queue,
and then check each individual channel for the caller-id.

Best regards,
Örn

On Tue, Jul 1, 2008 at 7:20 PM, Marcin J. Kowalczyk
<marcin.kowalczyk at ccig.pl> wrote:

> Hi,
>
>  Is there a way to show callerID of calls waiting in queue?
>     queue show
> shows only channel not callerID
>
>
> Cheers,
> Marcin
>
>
>
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