[asterisk-users] phpagi problem
VoIP Street
list at voipstreet.com
Tue Jul 18 14:36:44 MST 2006
Mauricio Mantilla wrote:
> Yeah, I wrote it on a different file and it worked, i guess there was
> some hidden character in the script that was messing it up.
> Thank you anyway,
>
> Mauricio Mantilla
>
> On 7/17/06, *Time Bandit* <timebandit001 at gmail.com
> <mailto:timebandit001 at gmail.com>> wrote:
>
> > #!/usr/bin/php -q
> > <?php
> > require('/var/lib/asterisk/agi-bin/phpagi.php');
> > $agi = new AGI();
> > $agi->say_digits(62410);
> > $cid = $agi->get_variable("dir");
> > $agi->say_digits($cid);
> > ?>
> >
> >
> > I'm getting this error:
> >
> > parse error, unexpected '=' on line 6
>
> I don't know why you're getting this error, it parse correctly here.
>
> But one thing is that the line "$agi->say_digits($cid);" won't work.
> When you do a get_variable, the result you get is an array, and the
> member holding the value is 'data'. So you have to write your line
> like this : $agi->say_digits($cid['data']);
>
> Check the documentation : http://phpagi.sourceforge.net/phpagi2/docs/
>
> hth
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dos2unix usually fixes these sorts of issues.
Just do something like this at the command line:
dos2unix filename filename
It removes a lot of the garbage that causes trouble with command line
PHP scripts and AGIs etc.
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