R: R: [Asterisk-Users] AT-320 + supervised transfer

[Giordano Grandis]

The procedure that will do asterisk is very nice ;) but whe it was available ?

Currently is there any way to emprove the transfer? I tryied the scenario that u suggest me but it doesn't work :| and i don't why.

Here my sip.conf for the phone, can u say me if there is somethingh wrong ?

[2391]
type=friend
username=2391
secret=2391
language=it
host=dynamic
context=intern
dtmfmode=rfc2833
callgroup=1
pickupgroup=1

I think is ok, maybe i have some problem on phone settings.Can I see your exmple phone setting ?

Thanks,
Giordano                    
                     

-----Messaggio originale-----
Da: asterisk-users-bounces at lists.digium.com [mailto:asterisk-users-bounces at lists.digium.com] Per conto di Gavin Hamill
Inviato: lunedì 30 maggio 2005 18.04
A: asterisk-users at lists.digium.com
Oggetto: Re: R: [Asterisk-Users] AT-320 + supervised transfer

On Monday 30 May 2005 16:19, Giordano Grandis wrote:
> Hi,
> Thanks for yuor answer.
>
> The boot time of the phone is very very fast, 10 sec to startup and 2 
> or 3 second to login to asterisk. I set the NTP server to 
> 255.255.255.255 so it don't try to get time.

Well, I run a local NTP server, so it's as fast plus has the correct time at the end :)

> I thinked carefully to your scenario and i am going to try it, but i 
> don't known if it could like to my customer
>
> I will try also to use CVS, but i am skeptic to utilize asterisk to 
> emprove atxfer...how asterisk emprove the atxfer ?  :|

When Asterisk does the transfer natively, the procedure is like this:

Call comes in, "hold on I'll try to transfer you". you dial *2 (or any sequence you define), speak to the remote party. If they want to speak to the caller, YOU hang up. If they don't, THEY hang up and you are returned to the original caller :)

> How do u set your sip.conf for the at-320 ?  Did u set the "canreinvite"
> option ?

[1300]
type=friend
username=1300
secret=<ahem>
host=dynamic
context=from-ip
nat=yes
canreinvite=no

Cheers,
Gavin.
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