[Asterisk-Users] app_queue, fewestcalls and leastrecent logic

[Richard Lyman]

well if you ask me, the leastrecent part would work if you reversed the 
logic on the metric.

my other last_used mod would do a time_t on that agent the last time it 
was 'tried' (ast_request'd) then (i was using arrays) qsort so that (new 
agents) '0' would be on top, and the agent that got the most recent 
attempt would be on the bottom '1057174447' (below is an example)

    -- sorted agent array: 317 last_used: 0
    -- sorted agent array: 318 last_used: 0
    -- sorted agent array: 319 last_used: 0
    -- sorted agent array: 300 last_used: 1057174447

that way, (for leastrecent anyway), you are always working with a full stack of agents.



Brian West wrote:

>First of all I would like to thank Mark for getting roundrobin to go
>roundrobin.  Good job.
>
>Now we have some options here for leastrecent and fewestcalls strategy. It
>needs some work on the logic and Mark recommend that I ask the list and
>get some input before he makes any changes to it.
>
>fewestcalls from what I have seen would always ring the agent with the
>fewestcalls first then go into roundrobin if that agent didn't answer.
>
>Next new caller would ring fewestcalls agent first then start roundrobin.
>
>What do you think should happen in fewestcalls?  Right now it just rings
>the agent with the fewestcalls over and over with current app_queue logic.
>
>leastrecent from what I have been looking at will ring the agent that has
>least recently take a call first then if they don't answer go into
>roundrobin.  Then the next new call coming from queue would first go to
>the leastrecent first then try every agent in roundrobin till answered
>then starting over again.  New caller from queue hits leastrecent agent
>first.
>
>Same thing happens in leastrecent strategy. The leastrecent agent will
>ring over and over with current app_queue logic.
>
>Now some of you might recommend autologoff options.  But that also might
>need some work.  I don't want to log off an agent for not answering the
>phone only once.  So here is how I would like to see autologoff work.
>
>Example:
>queue timeout = 20
>agent autologoff = 60
>
>The agent would have to not answer their phone 3 times in a row to get
>logged off.  As it stands now they did not answer just once and get logged
>off.  Thus allow for an employee to use the excuse for not working when
>they should be logged in and taking calls.
>
>Unless i'm wrong here.
>
>Please post your input on these options and how you would like them to see
>them function function.
>
>Thanks,
>Brian
>CWIS Internet Services
>
>
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