[Asterisk-code-review] func_channel: Added new OTHER_CHANNEL function (asterisk[master])
N A
asteriskteam at digium.com
Sat Aug 6 15:14:39 CDT 2022
Attention is currently required from: Joshua Colp, Mark Murawski.
N A has posted comments on this change. ( https://gerrit.asterisk.org/c/asterisk/+/15893 )
Change subject: func_channel: Added new OTHER_CHANNEL function
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Patch Set 7:
(1 comment)
Patchset:
PS7:
> There isn't really a defined methodical way. […]
I did some analysis and I don't think there is a locking risk presented.
When setting a variable, the channel lock is obtained. In the case of on a different channel, A will lock B's channel while it's setting the variable.
Now, suppose deadlock were to occur by A and B doing a simultaneous OTHER_CHANNEL write into each other's channels. If A started first, it would ref channel B and then lock it inside pbx_builtin_setvar_helper. Now suppose at this time, B wanted to set a variable on A's channel. This isn't problematic, because A never locks itself during execution, only the other channel (B). B is perfectly fine, therefore, to go ahead and lock any other channel, such as A or B. Doing so will not inhibit the first write in any way, so in no time at all, A will finish writing B and release B's lock.
Now suppose, hypothetically, that A were to lock itself as well as lock B during an OTHER_CHANNEL write. This would prevent B from writing to A because pbx_builtin_setvar_helper would block on getting A's channel lock. However, A is free to go ahead and finish its business and then release B's lock, and then release its own lock, so by the time B acquires A's lock, its own lock is also guaranteed to be free. (This isn't the current code model, the first case is, but this is just a hypothetical exercise).
Not the most rigorous proof, but I think this reasoning shows to confirm the current behavior is safe?
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Gerrit-Project: asterisk
Gerrit-Branch: master
Gerrit-Change-Id: I7492645ae4307553d0f586d78e13a4f586231fdf
Gerrit-Change-Number: 15893
Gerrit-PatchSet: 7
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