There is only one way to find out connecta.agi in /var/lib/asterisk/agi-bin directory by developing it yourself.<br><br><div class="gmail_quote">On Tue, Nov 1, 2011 at 6:57 PM, Thanasis <span dir="ltr"><<a href="mailto:thanasis@asyr.hopto.org">thanasis@asyr.hopto.org</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex;">on 11/01/2011 03:25 PM Danny Nicholas wrote the following:<br>
<div class="im">> One way to do this (there are probably more and better ways). Incoming call<br>
> to 123456789 launches meetme(1234,b(connecta.agi))<br>
> Connecta.agi calls lines B and C and connects them to meetme(1234).<br>
<br>
</div>Thanks, but could you be more elaborate please?<br>
Where can I find connecta.agi ?<br>
<div><div></div><div class="h5"><br>
><br>
> -----Original Message-----<br>
> From: <a href="mailto:asterisk-users-bounces@lists.digium.com">asterisk-users-bounces@lists.digium.com</a><br>
> [mailto:<a href="mailto:asterisk-users-bounces@lists.digium.com">asterisk-users-bounces@lists.digium.com</a>] On Behalf Of Thanasis<br>
> Sent: Tuesday, November 01, 2011 1:58 AM<br>
> To: Asterisk Users Mailing List - Non-Commercial Discussion<br>
> Subject: Re: [asterisk-users] custom automated meeting<br>
><br>
> I just want to make two specific sip phone sets to ring together, when<br>
> someone dials a specific incoming extension. And then, when each of the<br>
> ringed sets answers, to be placed immediately into meeting session with the<br>
> caller together with the other phone set.<br>
><br>
> Here is exactly what I mean:<br>
><br>
> Person A dials 123456789. Asterisk routes the incoming call and rings sip<br>
> phones B and C. Person B answers phone B and starts talking with person A,<br>
> while phone C keeps ringing. A minute later, and while A and B are still<br>
> talking together, person C answers phone C, and starts talking with A and B<br>
> together (that is aromatically all being placed in the same conference<br>
> session).<br>
><br>
> Is that doable?<br>
<br>
--<br>
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