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U can enter to the meetme conference w/ the m option.<br>
<br>
'm' — set monitor only mode (Listen only, no talking)<br>
<br>
Bruno.<br>
<br>
<a class="moz-txt-link-abbreviated" href="mailto:GDrayer@guesswho.com">GDrayer@guesswho.com</a> wrote:
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<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;">I have been successful
using ChanSpy on a standard Dial call
but when attempting to ChanSpy on an incoming call that has been added
to a
MeetMe conference (attempting to coach an agent that is speaking to a
conference
of callers) it seems to fail to connect to the channel. Here’s the
console dump:<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"><o:p> </o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- Accepting call
from '2154182700' to
'3399' on channel 0/18, span 4<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- Executing
[3399@from-internal:1]
Answer("Zap/90-1", "") in new stack<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- Executing
[3399@from-internal:2]
Read("Zap/90-1", "GOTDTMF|demo-instruct|1||1|1") in new
stack<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- Accepting a
maximum of 1 digits.<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- Playing
'demo-instruct' (language
'en')<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- User entered '5'<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- Executing
[3399@from-internal:3]
GotoIf("Zap/90-1", "5?9") in new stack<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- Goto
(from-internal,3399,9)<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- Executing
[3399@from-internal:9]
AGI("Zap/90-1", "simpleconf.agi") in new stack<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- Launched AGI
Script
/var/lib/asterisk/agi-bin/simpleconf.agi<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- Playing 'digits/5'
(language 'en')<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"> -- AGI Script
Executing Application:
(CHANSPY) Options: (Zap/73|wbq)<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"><o:p> </o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;">I verified Zap/73 is the
correct channel of the caller
currently in the conference I am attempting to ChanSpy on. Has anyone
done this before? I apologize in advance if my question lacks the
necessary information, I’m new to Asterisk.<o:p></o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;"><o:p> </o:p></span></font></p>
<p class="MsoNormal"><font face="Arial" size="2"><span
style="font-size: 10pt; font-family: Arial;">-George<o:p></o:p></span></font></p>
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