<div>Blind transfer is not possible via softkeys on the 7960 using chan_sccp. However, check your features.conf. You should have a line in there regarding blind transfer. I believe the default is #, but it recommended changing that to ##. I did this, and on my 7960s, you hit ## then the extension you wish to transfer to. This does requires use of the t or T dial command options. You'll have to look this up, as I can't remember offhand which is needed, and it depends on whether the 7960 is the caller or callee.
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<div>#2 and #3 I'll have to check on. If I remember correctly, it's pretty easy. <br><br> </div>
<div><span class="gmail_quote">On 6/27/06, <b class="gmail_sendername">Chris Bagnall</b> <<a href="mailto:asterisk@minotaur.cc">asterisk@minotaur.cc</a>> wrote:</span>
<blockquote class="gmail_quote" style="PADDING-LEFT: 1ex; MARGIN: 0px 0px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid">Greetings all,<br><br>Not specifically an asterisk query, but a couple of transfer queries that<br>I'm sure are obvious to folks who use these phones all the time:
<br><br>1) how does one do a blind transfer? When a call is answered and one hits<br>the transfer button, followed by an extension, one has to wait for the other<br>party to answer, then hit transfer again, before the call is released. I'm
<br>sure there must be an option to answer a call, then fire it straight off to<br>another extension without waiting for an answer?<br><br>2) if there are 2 incoming calls currently on the go (i.e. the first one has<br>been put on hold for the operator to answer the second call), how does one
<br>determine which call will be transferred when the transfer button is<br>pressed? Is there a way to select the source call for a transfer prior to<br>hitting transfer?<br><br>3) when handling 2 calls, how does one swap between them?
<br><br>These phones are running sccp through chan_sccp if that makes any difference<br>to operation.<br><br>Thanks in advance folks.<br><br>Regards,<br><br>Chris<br>--<br>C.M. Bagnall, Director, Minotaur I.T. Limited<br>
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