[asterisk-users] escaping regular expression
Klaus Darilion
klaus.mailinglists at pernau.at
Wed Feb 4 09:04:06 CST 2009
D Tucny schrieb:
> 2009/2/4 Klaus Darilion <klaus.mailinglists at pernau.at
> <mailto:klaus.mailinglists at pernau.at>>
>
> Hi!
>
> I am going nuts using REGEXP. I just want to verify if a variable
> contains a valid +E164 phone number.
>
> These, the the pattern is ^\+[0-9]+
>
> First I tried:
>
> Set(pattern=^\+[0-9]+);
> if (${REGEX("${pattern}" ${${var}})})
>
> but that does not work, the backslash is removed, as seen in the log
> file:
>
> func_strings.c: FUNCTION REGEX (^+[0-9]+)(+4312345
> <http://www.adaanumber.com/>)
>
> So, meanwhile I tried to escape the backslash. I tried:
> Set(pattern=^\\+[0-9]+);
> Set(pattern=^\\\+[0-9]+);
> Set(pattern=^\\\\+[0-9]+);
>
> But always the same result:
>
> func_strings.c: FUNCTION REGEX (^+[0-9]+)(+4312345)
>
> How can I solve this problem?
>
>
> Try something like... pattern=^[+]\{1\}[0-9]+
Are you sure? The \ should be in front of the +
klaus
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