[asterisk-users] Re: DUNDi with SIP

Watkins, Bradley Bradley.Watkins at compuware.com
Fri Aug 4 03:20:15 MST 2006


Easy, you change the fromuser=dundisip2 line to fromuser=dundisip1.
You're just matching the destination peer (dunsip2,
labpbx2.ipt.oneeighty.com) and sending the configured fromuser.
 
- Brad

________________________________

From: asterisk-users-bounces at lists.digium.com
[mailto:asterisk-users-bounces at lists.digium.com] On Behalf Of Douglas
Garstang
Sent: Thursday, August 03, 2006 4:18 PM
To: Asterisk Users Mailing List - Non-Commercial Discussion
Subject: RE: [asterisk-users] Re: DUNDi with SIP


*scream* I just got it to work with this...
 
180netsip => global_dundi_local,0,SIP,dundisip1/${NUMBER},nopartial
180netsip => global_dundi_local,0,SIP,dundisip2/${NUMBER},nopartial
 
[dundisip1]
type=friend
secret=password
insecure=very
context=global_dundi_local
host=labpbx1.ipt.oneeighty.com
qualify=no
username=dundisip1
fromuser=dundisip1
 
[dundisip2]
type=friend
secret=password
insecure=very
context=global_dundi_local
host=labpbx2.ipt.oneeighty.com
qualify=no
username=dundisip2
fromuser=dundisip2

It works... but the first system sends dundisip2 as the authid, not
dundisip1. I assume that's because it matches the host labpbx2. Well, it
should be sending dundisip1.... how can I get it to do that?
 
Doug.

	-----Original Message-----
	From: Watkins, Bradley [mailto:Bradley.Watkins at compuware.com]
	Sent: Thursday, August 03, 2006 2:06 PM
	To: Asterisk Users Mailing List - Non-Commercial Discussion
	Subject: RE: [asterisk-users] Re: DUNDi with SIP
	
	

	I forget if this does what you want, but try adding a fromuser
setting to yoyr peer entries.
	
	- Brad
	
	 -----Original Message-----
	From:   Douglas Garstang [mailto:dgarstang at oneeighty.com]
	Sent:   Thu Aug 03 15:58:50 2006
	To:     Asterisk Users Mailing List - Non-Commercial Discussion
	Subject:        RE: [asterisk-users] Re: DUNDi with SIP
	
	Brad...
	
	Here's the INVITE that the second asterisk box receives from
	the first Asterisk box, after the second asterisk box sends a
	Proxy auth message to the first. The first sends the dundisip
	userid, but for some reason the second asterisk box is
	matching it against the From: 3254101 address. Do I need more
	than just the two sip.conf entries, dundisip, and dundisip2
	as type=peer?
	
	Anyone?
	
	Doug.
	
	>
	> <-- SIP read from xxx.yyy.142.162:5060:
	> INVITE sip:9220370 at labpbx2.ipt.twoeighty.com SIP/2.0
	> Via: SIP/2.0/UDP
xxx.yyy.142.162:5060;branch=z9hG4bK047028fa;rport
	> From: "Chocolate Chip"
<sip:3254101 at xxx.yyy.142.162>;tag=as34445cb0
	> To: <sip:9220370 at labpbx2.ipt.twoeighty.com>
	> Contact: <sip:3254101 at xxx.yyy.142.162>
	> Call-ID: 7ca53bec20139d6a305b54936921b0ab at xxx.yyy.142.162
	> CSeq: 103 INVITE
	> User-Agent: Asterisk PBX
	> Max-Forwards: 70
	> Remote-Party-ID: "Chocolate Chip"
	> <sip:3254101 at xxx.yyy.142.162>;privacy=off;screen=no
	> Proxy-Authorization: Digest username="dundisip2",
	> realm="ipt.twoeighty.com", algorithm=MD5,
	> uri="sip:9220370 at labpbx2.ipt.twoeighty.com",
	> nonce="012b66e9",
	> response="bd5b3881afd0bdb827915a9eeb97dcd8", opaque=""
	> Date: Thu, 03 Aug 2006 19:52:26 GMT
	> Allow: INVITE, ACK, CANCEL, OPTIONS, BYE, REFER, SUBSCRIBE,
NOTIFY
	> Content-Type: application/sdp
	> Content-Length: 269
	>
	> v=0
	> o=root 16558 16559 IN IP4 xxx.yyy.142.162
	> s=session
	> c=IN IP4 xxx.yyy.142.162
	> t=0 0
	> m=audio 28454 RTP/AVP 0 18 101
	> a=rtpmap:0 PCMU/8000
	> a=rtpmap:18 G729/8000
	> a=fmtp:18 annexb=no
	> a=rtpmap:101 telephone-event/8000
	> a=fmtp:101 0-16
	> a=silenceSupp:off - - - -
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