[Asterisk-Users] Dial over IAX ahngs up after 3 rings

Thomas Haeger thomas.haeger at beronet.com
Tue Sep 23 08:50:33 MST 2003


I have tried it with a timeout and without...

here the * output for the first side:

 -- Starting simple switch on 'Zap/3-1'
    -- Executing Dial("Zap/3-1", "IAX2/useranme:passwd at 62.180.50.212/99033283077731") in new stack
    -- Called thaeger:hds71 at 62.180.50.212/99033283077731
    -- Call accepted by 62.180.50.212 (format ALAW)
    -- Format for call is ALAW
    -- Hungup 'IAX2[62.180.50.212:4569]/2'
  == No one is available to answer at this time
    -- Executing Hangup("Zap/3-1", "") in new stack
  == Spawn extension (guersel, 033283077731, 2) exited non-zero on 'Zap/3-1'
    -- Hungup 'Zap/3-1'



and here from the other side:

-- Accepting AUTHENTICATED call from 217.81.111.2, requested format = 8, actual format = 8
    -- Executing SetCallerID("IAX2[thaeger at 217.81.111.2:4569]/1", "033283077731") in new stack
    -- Executing Dial("IAX2[thaeger at 217.81.111.2:4569]/1", "Zap/g3/033283077731") in new stack
    -- Called g3/033283077731
    -- Channel 1, span 3 got hangup
    -- Hungup 'Zap/63-1'
  == No one is available to answer at this time
    -- Executing Hangup("IAX2[thaeger at 217.81.111.2:4569]/1", "") in new stack
  == Spawn extension (voipout, 99033283077731, 3) exited non-zero on 'IAX2[thaeger at 217.81.111.2:4569]/1'
    -- Hungup 'IAX2[thaeger at 217.81.111.2:4569]/1'

-----Ursprüngliche Nachricht-----
Von: asterisk-users-admin at lists.digium.com
[mailto:asterisk-users-admin at lists.digium.com]Im Auftrag von Eric
Wieling
Gesendet: Dienstag, 23. September 2003 17:12
An: asterisk-users at lists.digium.com
Betreff: Re: [Asterisk-Users] Dial over IAX ahngs up after 3 rings


It's not a general problem.  Can you give us more info like the Dial()
command and any output on the Asterisk console.  As good as some people
on this list are at solving problems, I'm not aware of any mindreaders
on the list.

On Tue, 2003-09-23 at 09:55, Thomas Haeger wrote:
> Hi all,
> can somebody explain this ?
> 
> Thanks,
> 
> Thomas.
> 
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