[Asterisk-Users] Regular expression matching for ":" - examples needed
John Todd
jtodd at loligo.com
Thu Sep 4 17:12:53 MST 2003
It is again perhaps my recent spate of bad sleeping that has
prevented my brain from wrapping around this explanation, or it is
perhaps my inherent hatred of regular expression syntax. However, I
have been unable to put this into a working form after staring at it
for a while and trying different recipes. If anyone wants to take a
stab at this, I'd appreciate it.
(from README.variables)
expr1 : expr2
The `:' operator matches expr1 against expr2, which must be a
regular expression. The regular expression is anchored to the
beginning of the string with an implicit `^'.
If the match succeeds and the pattern contains at least one regu-
lar expression subexpression `\(...\)', the string correspond-
ing to `\1' is returned; otherwise the matching operator
returns the number of characters matched. If the match fails and
the pattern contains a regular expression subexpression the null
string is returned; otherwise 0.
Examples I'd like to see:
1)
${FOO} contains 12345#
${HASH} contains #
If ${FOO} contains the contents of ${HASH} anywhere, go to 2. If not, goto 102
exten=> 123,1,GotoIf($[...???...]?2|102)
1.1)
If the last digit of ${FOO} is ${HASH}, then goto 2. If not, goto 102.
exten => 123,1,GotoIf($[...???...]?2|102)
JT
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